What is the value of (1+1/1) (1+1/2) (1+1/3) … (1+1/999) - mathselab.com

What is the value of (1+1/1) (1+1/2) (1+1/3) … (1+1/999)?

Question


What is the value of (1+1/1) (1+1/2) (1+1/3) … (1+1/999)?


A. 1000
B. 2000


Answer: A. 1000


Solution:


The Given Series is,

(1+1/1) (1+1/2) (1+1/3) … (1+1/999)

= (2/1)(3/2)(4/3)(5/4)…..(999/998)(1000/999)

= 1000 [all numerators and denominators cancels out remaining only 1000]


Hence, the series is (1+1/1) (1+1/2) (1+1/3) … (1+1/999) = 1000 .





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