Question
What is the value of (1+1/1) (1+1/2) (1+1/3) … (1+1/999)?
A. 1000
B. 2000
Answer: A. 1000
Solution:
The Given Series is,
(1+1/1) (1+1/2) (1+1/3) … (1+1/999)
= (2/1)(3/2)(4/3)(5/4)…..(999/998)(1000/999)
= 1000 [all numerators and denominators cancels out remaining only 1000]
Hence, the series is (1+1/1) (1+1/2) (1+1/3) … (1+1/999) = 1000 .