**Question**

`What is the value of (1+1/1) (1+1/2) (1+1/3) … (1+1/999)?`

`What is the value of (1+1/1) (1+1/2) (1+1/3) … (1+1/999)?`

A. 1000

B. 2000

**Answer: A. 1000**

**Solution:**

The Given Series is,

**(1+1/1) (1+1/2) (1+1/3) … (1+1/999)**

= (2/1)(3/2)(4/3)(5/4)…..(999/998)(1000/999)

= 1000 [all numerators and denominators cancels out remaining only 1000]

Hence, the series is **(1+1/1) (1+1/2) (1+1/3) … (1+1/999) = 1000** .