The sum of the present ages of a son and his father is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, what will be son's age - www.mathselab.com

The sum of the present ages of a son and his father is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, what will be son’s age?

Question


The sum of the present ages of a son and his father is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, what will be son's age?


A. 22 years
B. 23 years
C. 20 years
D. 21 years


Answer: C. 20 years


Solution:


Let the present age of the son = x

Then, present age of the father = ( 60 − x )


Six years ago father’s age was 5 times the age of the son

⇒ ( 60 − x ) − 6 = 5 ( x − 6 )

⇒ 84 = 6x

⇒ x = 84 / 6 = 14


Son’s age after 6 years = x + 6

= 14 + 6

= 20


Hence, The Son’s age after 6 years is 20 years.







Read more


A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27 . How old is B?What number should replace the question mark?
What number should replace the question mark?What number should logically replace the question mark?

Leave a Reply

Your email address will not be published.