A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27 . How old is B - www.mathselab.com

A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27 . How old is B?

Question


A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27 . How old is B?


A. 7
B. 8
C. 9
D. 10


Answer: D = 10


Solution:


Let age of C = x

age of B = 2x

age of A = 2 + 2x


Total age of A,B and C = 27

⇒ ( 2 + 2x ) + 2x + x = 27

⇒ 5x = 25

⇒ x = 25 / 5 = 5


B’s age = 2x = 2 × 5 = 10


Hence, The Answer is 10.




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