A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27. How old is B - www.mathselab.com

A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27. How old is B?

Question


A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27. How old is B?

A. 7
B. 8
C. 9
D. 10


Answer: D. 10


Solution:

Let age of C = x
age of B = 2x
age of A = 2 + 2x

Total age of A,B and C = 27

⇒ (2 + 2x) + 2x + x = 27

⇒ 5x = 25

⇒ x = 25/5 = 5

B’s age = 2x = 2 × 5 = 10

Hence, The answer is 10.





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