Which of the following integers has the most number of divisors - mathselab.com

Which of the following integers has the most number of divisors?

Question


Which of the following integers has the most number of divisors?


A. 101
B. 176
C. 99
D. 182


Answer: B. 176


Solution:


99 = 1 × 3 × 3 × 11

=> Divisors of 99 are 1, 3, 11, 9, 33 and 99


101 = 1 × 101

=> Divisors of 101 are 1 and 101


182 = 1 × 2 × 7 × 13

=> Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182


176 = 1 × 2 × 2 × 2 × 2 × 11

=> Divisors of 176 are 1, 2, 11, 4, 22, 8, 44, 16, 88, 176


Hence, 176 has most number of divisors.






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