## Question

**Which of the following integers has the most number of divisors?**

A. 101

B. 176

C. 99

D. 182

**Answer: B. 176**

**Solution:**

**99** = 1 × 3 × 3 × 11

=> Divisors of 99 are 1, 3, 11, 9, 33 and 99

**101** = 1 × 101

=> Divisors of 101 are 1 and 101

**182** = 1 × 2 × 7 × 13

=> Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182

**176** = 1 × 2 × 2 × 2 × 2 × 11

=> Divisors of 176 are 1, 2, 11, 4, 22, 8, 44, 16, 88, 176

**Hence, 176 has most number of divisors.**