Question
A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly?
A. 14
B. 16
C. 18
D. 12
Answer: B
Solution:
Suppose the boy got x sums right and 2x sums wrong. Then,
x + 2x = 48
⇒ 3x = 48
⇒ x = 16.
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