Question
The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is _____
A. 40
B. 30
C. 28
D. 24
Answer: C
Solution:
We know that x^2 + (x + 2)^2 = 394
=> x^2 + x^2 + 4x + 4 = 394
=> 2 x^2 +4x – 390 = 0
=> x^2 + 2x – 195 = 0
=> (x +15) (x-13) = 0
=> x = 13
We know Required sum = 13 +15 =28