## Question

**The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is _____**

A. 40

B. 30

C. 28

D. 24

**Answer:** C

**Solution:**

We know that x^2 + (x + 2)^2 = 394

=> x^2 + x^2 + 4x + 4 = 394

=> 2 x^2 +4x – 390 = 0

=> x^2 + 2x – 195 = 0

=> (x +15) (x-13) = 0

=> **x = 13**

We know Required sum = 13 +15 **=28**