## Question

**In a cricket match, five batsmen P, Q, R, S and T scored an average of 36 runs. S Scored 5 more than T; T scored 8 fewer than P; Q scored as many as S and T combined; and Q and R scored 107 between them. How many runs did T score? **

A. 29

B. 28

C. 24

D. 20

**Answer:** D

**Solution:**

Let the runs scored by P, Q, R, S and T be a, b, c, d and e

From given data,

a + b + c + d + e = 36 x 5 = 180

b + c = 107

Let a = x

e = x-8

d = x-3

now 3x – 11 + 107 = 180

3x = 84

x = 28

e’s score = 28-8 = 20