Question
In a cricket match, five batsmen P, Q, R, S and T scored an average of 36 runs. S Scored 5 more than T; T scored 8 fewer than P; Q scored as many as S and T combined; and Q and R scored 107 between them. How many runs did T score?
A. 29
B. 28
C. 24
D. 20
Answer: D
Solution:
Let the runs scored by P, Q, R, S and T be a, b, c, d and e
From given data,
a + b + c + d + e = 36 x 5 = 180
b + c = 107
Let a = x
e = x-8
d = x-3
now 3x – 11 + 107 = 180
3x = 84
x = 28
e’s score = 28-8 = 20
