## Question

**If 1 1 1 1 = R**

2 2 2 2 = T

3 3 3 3 = E

4 4 4 4 = N

2 2 2 2 = T

3 3 3 3 = E

4 4 4 4 = N

**Then 5 5 5 5 = ?**

A) Y

B) Z

C) T

D) X

**Answer: A. Y**

**Solution:**

If you add all the terms of the LHS of equality, then the last letter of the sum written in words would give you the RHS.

1 + 1 + 1 + 1 = 4 = FOU**R**

2 + 2 + 2 + 2 = 8 = EIGH**T**

3 + 3 + 3 + 3 = 12 = TWELV**E**

4 + 4 + 4 + 4 = 16 = SIXTEE**N**

So, following the same pattern.

**5 + 5 + 5 + 5 = 20 = TWENTY**

**That gives us our answer to 5 5 5 5 = “Y”.**