Question
If 1 1 1 1 = R
2 2 2 2 = T
3 3 3 3 = E
4 4 4 4 = N
Then 5 5 5 5 = ?
A) Y
B) Z
C) T
D) X
Answer: A. Y
Solution:
If you add all the terms of the LHS of equality, then the last letter of the sum written in words would give you the RHS.
1 + 1 + 1 + 1 = 4 = FOUR
2 + 2 + 2 + 2 = 8 = EIGHT
3 + 3 + 3 + 3 = 12 = TWELVE
4 + 4 + 4 + 4 = 16 = SIXTEEN
So, following the same pattern.
5 + 5 + 5 + 5 = 20 = TWENTY
That gives us our answer to 5 5 5 5 = “Y”.
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Can you solve the missing number?
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