The age of a father is twice that of an elder son. Ten years hence the age of the father will be three times that of the younger son. If the difference in ages of the two sons is 15 years, the age of the father is
Let the age of the elder son be x years.
Then, the age of the younger son = (x – 15) years; the age of the father = 2x years.
So, 2x + 10 = 3(x – 15 + 10)
⇒ 2x + 10 = 3x – 15
⇒ x = 25.
∴ Father’s age = 2x = 50 years